View Full Version : Maths congruence question3
ana_mujahid
03-02-08, 06:43 PM
4) PQRS is a square and equilateral triangles PQA and RQB are drawn with A inside and B outside the square.
By considering triangles PQR and AQB, prove that AB is equal to PR
how does the shape look like,
use paint or somfink and attach please :)
thanks
need today (3hours max)
Ibn Al-Jarrah
03-02-08, 06:59 PM
P __________ R
|\ |\
| \ | \ B
| / A | /
|/__________|/
Q S
the triangles all have 60 degree angles
since PR is a straight line, and angle A and B are equal, they will both be parallel
ana_mujahid
03-02-08, 07:12 PM
P __________ R
|\ |\
| \ | \ B
| / A | /
|/__________|/
Q S
the triangles all have 60 degree angles
since PR is a straight line, and angle A and B are equal, they will both be parallel
can u use paint and upload it, or send it to me on msn (ill pm if u want) cuz i cant see it
mizfissy815
03-02-08, 07:14 PM
Should look something like that I reckon...
My reasoning is slightly different to Ibn Jarrah's.
Since PRQ is an isosceles triangle where PR=PQ (with QR as the hypotenuse of that triangle) and PQA is an equilateral triangle, where PQ=QA=PA....QA= PR.
Since QRB is an equilateral, QR=QB=BR ....QAB is also an isosceles triangle, where QA=AB...
AB=PR.
You could alternatively use the angles argument.
ana_mujahid
03-02-08, 07:27 PM
Should look something like that I reckon...
My reasoning is slightly different to Ibn Jarrah's.
Since PRQ is an isosceles triangle where PR=PQ (with QR as the hypotenuse of that triangle) and PQA is an equilateral triangle, where PQ=QA=PA....QA= PR.
Since QRB is an equilateral, QR=QB=BR ....QAB is also an isosceles triangle, where QA=AB...
AB=PR.
You could alternatively use the angles argument.
so wat congruent rule is it? SAS?
mizfissy815
03-02-08, 07:35 PM
so wat congruent rule is it? SAS?
Edit- No, you're right it is SAS.
ana_mujahid
03-02-08, 07:54 PM
i c
thanks Ibn Jarrah and mizfissy
mizfissy815
03-02-08, 07:54 PM
Ok, take a look at this pic.
Ignoring everything else, triangle PRQ is an isosceles where angle PQR and PRQ = 45...(since angle QPR is clearly 90.)
We already know that PQ = QA....and QR =AB and the angle between QA and QB is also 45. So, AB = PR and the rule is SAS.
ana_mujahid
03-02-08, 07:55 PM
Ok, take a look at this pic.
Ignoring everything else, triangle PRQ is an isosceles where angle PQR and PRQ = 45...(since angle QPR is clearly 90.)
We already know that PQ = QA....and QR =AB and the angle between QA and QB is also 45. So, AB = PR and the rule is SAS.
:up:
:jkk: sister :)
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