need maths help NOW (2MRO MOCK)

[ana_mujahid]

Show that the equation

[2/(x+1)] - [1/(x+2)] = 1/2

can be written in the form x^2-x-4=0

[~Unity~]

Maths? :zzz:

Why do people never need help with Literature?

Sorry I know you needed real help :o:outta:

[ana_mujahid]

Maths? :zzz:

Why do people never need help with Literature?

Sorry I know you needed real help :o:outta:

i got literature next week, u can help me then :up: :p


need reply asap!!

[lao tzu]

Show that the equation

[2/(x+1)] - [1/(x+2)] = 1/2

can be written in the form x^2-x-4=0

Clear the denominators:

2 (x+1)(x+2) [2/(x+1)] - 2 (x+1)(x+2) [1/(x+2)] = 2 (x+1)(x+2) (1/2)

4 (x+2) - 2 (x+1) = (x+1)(x+2)

Collect terms on the LHS:

4 (x+2) - 2 (x+1) - (x+1)(x+2) = 0

Clear the parentheses:

4x + 8 - 2x - 2 - x^2 - 3x - 2 = 0

Combine terms:

- x^2 - x + 4 = 0

Swap signs:

x^2 + x - 4 = 0

Looks like a sign error in your question ... cause my math is right.

[ana_mujahid]

Clear the denominators:

2 (x+1)(x+2) [2/(x+1)] - 2 (x+1)(x+2) [1/(x+2)] = 2 (x+1)(x+2) (1/2)

4 (x+2) - 2 (x+1) = (x+1)(x+2)

Collect terms on the LHS:

4 (x+2) - 2 (x+1) - (x+1)(x+2) = 0

Clear the parentheses:

4x + 8 - 2x - 2 - x^2 - 3x - 2 = 0

Combine terms:

- x^2 - x + 4 = 0

Swap signs:

x^2 + x - 4 = 0

Looks like a sign error in your question ... cause my math is right.


my sign's are correct, i double checked the question,
but i see where ur coming from

thanks

[ammarcool]

my sign's are correct, i double checked the question,
but i see where ur coming from

thanks

brother answer is => x^2 + x - 4 = 0, double check your sum. :)