Titration 2

[ana_mujahid]

im starting a new thread because you might not check the old one.
anyways...


here is the question -->

[NaOH] = (any number)M
[HCL] = ?

find the concentration on HCL needed to neutralise NaCl

so i put the HCL in the burette using a funnel
put the NaOH (alkaline) into the conical flask
i add a few drops of methyl orange
i add acid, drop by drop, from the burette into the flask until the solution become neutral. take note of how much acid was added.

this is use this formula >>>



C (of acid) = [C (of alkaline) x V (of alkaline)] ÷ V (of acid)

So C1 = [C2 x V2] ÷ V1

and this give me the concentration of the acid added.

so if the NaOH was 1M, i added 20ml of HCl to the NaOH, and 10cm^3 of NaOH in the flask the answer become
[1x10]÷20 = 0.5M

is this method correct? if not why?

is there anyother methods?

thanks

-ana

[mu2lim]

Assalamu Alaikum Ana_Mujahid

This is how I would do it.

NaOH + HCl ---> NaCl + H20

According to the equation,

1) Moles of NaOH = Moles of NaCl

Therefore using the formula -> moles = volume (dm3) * concentration

2) Moles of NaOH = 1 * (10/1000) = 0.01

3) Moles of HCl = 0.01

4) Concentration of HCl = moles/volume (dm3) = 0.01/0.02 = 0.5M

0.02 = 20/1000 (volume of HCl in dm3)

Hope this helps

From your brother in Islam

Wassalam

[ana_mujahid]

:jkk: akhi mu2lim

both ways are valid