MATHSssS QuIZzEe

[Asma.Haddad]

Salamu 3alaykum, Here's another quize.. this time its to do wid maths.... each line a rep ;).. So what is everyone waiting for..

FIND THE THREE NEXT NUMBERS IN EACH PATTERN:

9,15,7,13,5,11, .... .... ....

1,2,4,8,16, .... .... ....

29,27,25,23,21, .... .... ....

36,40,44,48,52, .... .... ....

5,7,5,8,5,9, .... .... ....

1,4,7,10,13, .... .... ....

Wassalamu Alaykum

Asma.Haddad

[Hafsah]

:vomit:

i hate series and sequences

[Hafsah]

9,15,7,13,5,11, .... .... ....

1,2,4,8,16, 32, 64, 128.... .... ....

29,27,25,23,21, 19, 17, 15.... .... ....

36,40,44,48,52, 56, 60, 64.... .... ....

5,7,5,8,5,9, 5, 10, 5 .... ....

1,4,7,10,13, 16, 19 , 22..

[Irfan GBH]

9,15,7,13,5,11, 3, 9, 1,

1,2,4,8,16, 32, 64, 128

29,27,25,23,21,19,17, 15

36,40,44,48,52, 56, 60, 64

5,7,5,8,5,9, 5, 10, 5

1,4,7,10,13, 16, 19, 22

[Niqaabi]

Key: M = Method

9,15,7,13,5,11, 3, 9, 1 (M = +6 -8)

1,2,4,8,16, 32, 64, 128 (M = x2)

29,27,25,23,21, 19, 17, 15 (M = -2)

36,40,44,48,52, 56, 60, 64 (M = +4)

5,7,5,8,5,9, 5, 10, 5 (M = x+n-n, also known as oscilating pattern)

1,4,7,10,13, 16, 19, 22 (M = +3)

[(*_Hamzah]

This is two easy, can't we skip the basic and move to Algebra and trigonometry

[alld]

Salamu 3alaykum, Here's another quize.. this time its to do wid maths.... each line a rep ;).. So what is everyone waiting for..

FIND THE THREE NEXT NUMBERS IN EACH PATTERN:

9,15,7,13,5,11, ..3.. ..9.. ..1..
1,2,4,8,16, ..32.. .64... .128...

29,27,25,23,21, ..19.. 17.... ..15..

36,40,44,48,52, .56... .60... .64...

5,7,5,8,5,9, ...5. .10... ..5..

1,4,7,10,13, ..16.. ..19.. .22...Wassalamu Alaykum

Asma.Haddad

:up:

[scribble]

This is two easy, can't we skip the basic and move to Algebra and trigonometry

:rolleyes: Hah! I can do Algebra and Trigononmetry too. :p

[Reptile]

lol this is harder than it looks

divide btw the numbers after x are meant to be powers

x-4 by 2x6- 11x5 + 14x4 - 16x3 + 36x2 - 10x - 24

enjoy! :D

[Irfan GBH]

lol this is harder than it looks

divide btw the numbers after x are meant to be powers

x-4 by 2x6- 11x5 + 14x4 - 16x3 + 36x2 - 10x - 24

enjoy! :D

I don't understand what you said, please use correct english and correct mathematical terms to describe what we must do.

[Niqaabi]

yeh can you use the following please

Addition +
subtraction -
multiplication *
Division /
equals =
number of x or n
frequency f
power of ^

[Masumah]

Salamu 3alaykum, Here's another quize.. this time its to do wid maths.... each line a rep ;).. So what is everyone waiting for..

FIND THE THREE NEXT NUMBERS IN EACH PATTERN:

9,15,7,13,5,11, .... .... ....

1,2,4,8,16, .... .... ....

29,27,25,23,2, .... .... ....

36,40,44,48,52, .... .... ....

5,7,5,8,5,9, .... .... ....

1,4,7,10,13, .... .... ....

Wassalamu Alaykum

Asma.Haddad


Answers:

line 1 : 3, 9,1

line 2: 32, 64, 128

line 3: 19, 17, 15

line 4: 56, 60, 64

line 5: 5, 10. 5

line 6: 16, 19, 22

These were easy!

[imran1976]

Answers:

line 1 : 3, 9,1

line 2: 32, 64, 128

line 3: 19, 17, 15

line 4: 56, 60, 64

line 5: 5, 10. 5

line 6: 16, 19, 22

These were easy!

ya they were easy coz it were already solved in above posts :p

[Masumah]

lol this is harder than it looks

divide btw the numbers after x are meant to be powers

x-4 by 2x6- 11x5 + 14x4 - 16x3 + 36x2 - 10x - 24

enjoy! :D


r we ment to simplify this or work out wot x is?

[Masumah]

ya they were easy coz it were already solved in above posts :p

i dint copy :rolleyes:

[alld]

lol this is harder than it looks

divide btw the numbers after x are meant to be powers

x-4 by 2x6- 11x5 + 14x4 - 16x3 + 36x2 - 10x - 24

enjoy! :D

scan the question and import it here so that it can be solved . you can't have value for x unless there are other equations .

[Reptile]

my english and mathematical terms were perfectly fine

i will reirterate again you have to divide x-4 by 2x6 - 11x5 + 14x4 - 16x3 + 36x2 - 10x - 24

and the numbers after x in bold are powers

using the method of long division to find a quaderatic and perhaps a reminder and you dont need to solve x

[Masumah]

der is no remainder for the above problem. The answer i got is as follows :

2x5- 3x4+ 2x3- 8x2+ 4x+ 6

The numbers in bold are powers.

[Masumah]

i will post the workin out later inshAllah :)

[umm_huraiyrah]

9,15,7,13,5,11, .... .... ....

1,2,4,8,16, 32, 64, 128.... .... ....

29,27,25,23,21, 19, 17, 15.... .... ....

36,40,44,48,52, 56, 60, 64.... .... ....

5,7,5,8,5,9, 5, 10, 5 .... ....

1,4,7,10,13, 16, 19 , 22..

:rotfl: the first one didn't make sense to you either huh?

Habiba

[Hafsah]

hmm...i vaguely remember algebraic division...you gotta substitute things.....hmm..and theres a formula you can use (somtimes)?

[Reptile]

der is no remainder for the above problem. The answer i got is as follows :

2x5- 3x4+ 2x3- 8x2+ 4x+ 6

The numbers in bold are powers.

Mashallah correct sis! :up:

[Reptile]

i'll do the method insha'allah soon to explain how u do it

[slmz :)]

hmm.... what happened to Un=a(r-1)

or suttin like that...

[Masumah]

tried showing the workin out on here..dint work so gonna upload the doc version inshAllah

[Masumah]

Mashallah correct sis! :up:


its bin two years now since my maths Alevel i miss it soo much..was so happy u posted one up...i ahd forgotten how to do it..but a quick dig in my books and voila..ive still got my tuch..post up sum more sis inshAllah :)

[Reptile]

lol great

im doing it at the moment, i'll give some stat one 2moro have headache at the moment and do not want it to get worse!

[Masumah]

np..do a statistic 2 module question..i did ver good on that paper alhamdulillah 97% :)

[Masumah]

oh cum on post one up :(